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最后更新时间:2008-03-07
在spring2中配置JPA的问题 望哪位大侠解决 郁闷我好几天了
错误代码如下 Caused by: org.springframework.beans.factory.BeanCreationException: Error creating bean with name '(inner bean)': Cannot resolve reference to bean 'JpaTransactionManager' while setting bean property 'transactionManager'; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'JpaTransactionManager' defined in class path resource [spring/applicationContext-test-jpa.xml]: Cannot resolve reference to bean 'entityManagerFactory' while setting bean property 'entityManagerFactory'; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'entityManagerFactory' defined in class path resource [spring/applicationContext-test-jpa.xml]: Invocation of init method failed; nested exception is java.lang.IllegalArgumentException: Cannot parse persistence unit from class path resource [persistence.xml] at org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveReference(BeanDefinitionValueResolver.java:275) at org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveValueIfNecessary(BeanDefinitionValueResolver.java:104) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.applyPropertyValues(AbstractAutowireCapableBeanFactory.java:1172) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.populateBean(AbstractAutowireCapableBeanFactory.java:940) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:437) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory$1.run(AbstractAutowireCapableBeanFactory.java:383) at java.security.AccessController.doPrivileged(Native Method) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:353) at org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveInnerBean(BeanDefinitionValueResolver.java:219) ... 32 more 一直想做的Spring+Jpa的Demo,各位老大看看这个什么原因啊 我是在Myeclipse开发的,工程路径如下: XXproject + src + test + resources ++spring +++persistence.xml +++applicationContext.xml +++applicationContext-test-jpa.xml applicationContext-test-jpa.xml 如下: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p" xmlns:aop="http://www.springframework.org/schema/aop" xmlns:tx="http://www.springframework.org/schema/tx" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-2.5.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-2.5.xsd" default-autowire="byName" default-lazy-init="true" > <description>所有Service/DAO的集中配置文件,可按模块划分文件</description> <!-- 主要用于JPA非JavaEE5 的生产环境(如Tomcat)与开发测试环境 --> <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="persistenceXmlLocation" value="persistence.xml" /> <property name="persistenceUnitName" value="basicServicePU" /> <property name="dataSource" ref="dataSource" /> </bean> <bean id="JpaTransactionManager" class="org.springframework.orm.jpa.JpaTransactionManager"> <property name="entityManagerFactory" ref="entityManagerFactory" /> </bean> <!-- JTA环境的事务配置 <bean id="myTxManager" class="org.springframework.transaction.jta.JtaTransactionManager or WebLogicJtaTransactionManager"/> --> <tx:annotation-driven transaction-manager="JpaTransactionManager" /> <bean class="org.springframework.beans.factory.annotation.RequiredAnnotationBeanPostProcessor" /> <!-- User Module --> <bean id="userManager" class="org.jdonee.dao.UserJpaManager" /> <bean id="userJpaDao" class="org.jdonee.dao.UserJpaDao"/> </beans> 声明:JavaEye文章版权属于作者,受法律保护。没有作者书面许可不得转载。
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