webwork2.24 Action注入问题[已解决]

spring2.08 webwork2.24
注入Action中的service出现问题，注入的service，和引用的service不是同一个对象。
无论是不是singleton都出现execute方法里面引用的service为null，声明为singleton="true"时初始化时setter方法里的service有效。
或者把service声明为static的也没问题。

Action

public class SystemAction extends ActionSupport implements ModelDriven{
    SystemModel sm = new SystemModel();
    private SystemService systemService;
    
    public String execute() throws Exception {
        System.out.println("in execute systemservice is "+systemService);
        systemService.TestSystemDAO();
        return SUCCESS;
    }

..setter..省略

Action的注入

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE beans PUBLIC "-//SPRING//DTD BEAN//EN" "http://www.springframework.org/dtd/spring-beans.dtd">
<beans>
		<bean id="systemAction" class="net.xx.control.action.SystemAction" singleton="false">
		<property name="systemService">
			<ref bean="userService"/>
		</property>
		</bean>
</beans>

xwork.xml

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xwork PUBLIC "-//OpenSymphony Group//XWork 1.0//EN" "http://www.opensymphony.com/xwork/xwork-1.0.dtd">
<xwork>
	<include file="webwork-default.xml" />
	<package name="default" extends="webwork-default">
		<interceptors>
			<interceptor-stack name="modelParamsStack">
				<interceptor-ref name="params" />
				<interceptor-ref name="model-driven"/>
			</interceptor-stack>
		</interceptors>
	</package>
<include file="net\xx\control\config\webwork-user.xml"/>
</xwork>

webwork-user.xml

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xwork PUBLIC "-//OpenSymphony Group//XWork 1.0//EN" "http://www.opensymphony.com/xwork/xwork-1.0.dtd">
<xwork>
 <package name="login" extends="webwork-default" namespace="/user">  
	<action name="login" class="net.xx.control.action.SystemAction">
			<result name="success" type="dispatcher">
				<param name="location">/index.jsp</param>
			</result>
			<result name="error" type="dispatcher">
				<param name="location">/login.jsp</param>
			</result>
		<interceptor-ref name="modelParamsStack"/>
	</action>
 </package> 
</xwork>

web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.4" 
	xmlns="http://java.sun.com/xml/ns/j2ee" 
	xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
	xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee 
	http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
	<servlet>
		<servlet-name>webwork</servlet-name>
		<servlet-class>
			com.opensymphony.webwork.dispatcher.ServletDispatcher
		</servlet-class>
		<init-param>
			<param-name>contextConfigLocation</param-name>
			<param-value>/WEB-INF/applicationContext*.xml</param-value>
		</init-param>
	<load-on-startup>1</load-on-startup>
	</servlet>

	<servlet-mapping>
		<servlet-name>webwork</servlet-name>
		<url-pattern>*.action</url-pattern>
	</servlet-mapping>
<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

	<context-param>
		<param-name>contextConfigLocation</param-name>
		<param-value>/WEB-INF/applicationContext*.xml</param-value>
	</context-param> 
	 	<filter> 
        <filter-name>openSessionInViewFilter</filter-name> 
        <filter-class>org.springframework.orm.hibernate3.support.OpenSessionInViewFilter</filter-class> 
	</filter> 

	<filter-mapping> 
        <filter-name>openSessionInViewFilter</filter-name> 
        <url-pattern>/*</url-pattern> 
	</filter-mapping>
</web-app>

在javae也搜索到类似的问题，但。。还是没解决
http://www.javaeye.com/post/139291

解决了
原来默认的是根据name来注入action的service
在webwork.properties
声明一下，就行了。。。吐血。。。
webwork.objectFactory.spring.autoWire = type

webwork.properties
webwork.objectFactory=spring

我在webwork.properties
里面声明了

我看你要被投为新手贴了

。。。。。。。。。。

这个一看webwork源码就知道了

建议还是多看下源码，别会用了就好，应该去理解本质原理

或者将

 <action name="login" class="net.xx.control.action.SystemAction">.....   

改成

 <action name="login" class="systemAction">.....